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NTPC Graduate Tier 1 2025 Shift-2 📅 05 Jun, 2025

From a taxi stand, two cabs start at a speed of 74 km/hr at an interval of 28 minutes, both cabs travelling in the same direction. A man coming in the opposite direction towards the taxi stand meets the cabs at an interval of 10 minutes. Find the speed (in km/hr) of the man.

A
128.8
B
133.2
C
143.1
D
125.5
Result Summary
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APEDIA

NTPC Graduate Tier 1
2025 • 05 Jun, 2025 • Shift-2
From a taxi stand, two cabs start at a speed of 74 km/hr at an interval of 28 minutes, both cabs travelling in the same direction. A man coming in the opposite direction towards the taxi stand meets the cabs at an interval of 10 minutes. Find the speed (in km/hr) of the man.
Correct Answer
133.2
Distance Metric: The actual physical distance separating the two cabs is the distance covered by a cab in 28 minutes. Distance = 74 * (28/60) km.Relative Speed ......
💡 Analysis & Explanation
Distance Metric
The actual physical distance separating the two cabs is the distance covered by a cab in 28 minutes. Distance = 74 * (28/60) km.
Relative Speed Engine
Since the man moves opposite to the cabs, their relative approach speed is (74 + v) km/hr, where v is the man's speed.
Equating Scenarios
He bridges this exact distance in 10 minutes. So, Distance = (74 + v) * (10/60).
Equation Resolution
74 * 28 = (74 + v) * 10 → 2072 = 740 + 10v → 10v = 1332 → v = 133.2 km/hr.
Conclusion
The speed of the approaching man is 133.2 km/hr.