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NTPC Graduate Tier 1 2025 Shift-2 📅 06 Jun, 2025

Tanveer starts from Point B and drives 2 km towards west. He then takes a right turn, drives 4 km, turns left and drives 5 km. He then takes a right turn and drives 3 km. He takes a final right turn, drives 7 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point B again (all turns are 90° turns only unless specified)?

A
5 km south
B
7 km south
C
6 km south
D
4 km south
Result Summary
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APEDIA

NTPC Graduate Tier 1
2025 • 06 Jun, 2025 • Shift-2
Tanveer starts from Point B and drives 2 km towards west. He then takes a right turn, drives 4 km, turns left and drives 5 km. He then takes a right turn and drives 3 km. He takes a final right turn, drives 7 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point B again (all turns are 90° turns only unless specified)?
Correct Answer
7 km south
Mapping the Initial Journey: Designate Point B as the coordinate origin (0,0). Moving 2 km West shifts his position to (-2, 0). Taking a 90° right turn aligns ......
💡 Analysis & Explanation
Mapping the Initial Journey
Designate Point B as the coordinate origin (0,0). Moving 2 km West shifts his position to (-2, 0). Taking a 90° right turn aligns him North; driving 4 km brings him to (-2, 4).
Continuing the Path
A subsequent left turn points him West again. Driving 5 km places him at (-7, 4). Another right turn faces him North, and moving 3 km results in coordinates (-7, 7).
Determining the Final Position
His final right turn directs him East. By driving exactly 7 km East, he perfectly neutralizes his cumulative westward movements (-7 + 7 = 0). He halts at Point P, which rests directly on the Y-axis at (0, 7).
Return Trajectory Calculation
To navigate back to his starting point B (0,0) from P (0, 7) via the shortest route, he must travel straight down the Y-axis.
Conclusion
Consequently, he must drive 7 km straight in the South direction.