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NTPC Graduate Tier 1 2025 Shift-2 📅 05 Jun, 2025

When x is added to each of 26, 40, 22 and 34, then the numbers so obtained, in this order, are in proportion. Then, if 4x : y :: y : (7x-6), and y > 0 what is the value of y?

A
2
B
8
C
3
D
9
Result Summary
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APEDIA

NTPC Graduate Tier 1
2025 • 05 Jun, 2025 • Shift-2
When x is added to each of 26, 40, 22 and 34, then the numbers so obtained, in this order, are in proportion. Then, if 4x : y :: y : (7x-6), and y > 0 what is the value of y?
Correct Answer
8
Proportional Framework: Numbers are strictly in proportion if a/b = c/d. Modifying the array yields: (26+x)/(40+x) = (22+x)/(34+x).Cross Multiplication Phase: E......
💡 Analysis & Explanation
Proportional Framework
Numbers are strictly in proportion if a/b = c/d. Modifying the array yields: (26+x)/(40+x) = (22+x)/(34+x).
Cross Multiplication Phase
Expand the brackets: (26+x)(34+x) = (40+x)(22+x). This mathematically unfolds as 884 + 60x + x² = 880 + 62x + x².
Variable Isolation
The x² terms dynamically cancel out from both ends. Rearranging the remaining terms leaves 2x = 4, definitively proving x = 2.
Secondary Ratio Application
Inject x=2 into the secondary condition 4x : y :: y : (7x-6). This outputs 8 : y :: y : (14-6), simplifying structurally to 8/y = y/8.
Final Resolution
Cross multiplying yields y² = 64. Taking the root, and acknowledging the strict rule y > 0, we find y = 8.
Conclusion
The derived positive value for y stands perfectly at 8.