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NTPC Graduate Tier 1 2025 Shift-3 📅 05 Jun, 2025

A group of numbers and symbols is coded using letter codes as per the codes given below and the conditions that follow.

Number/symbol4@7#3&82A9$6+
CodeHAJBKCLDMENFG


Conditions:
  1. If the first element is a number and the last a symbol, the codes for these two (the first and the last elements) are to be interchanged.
  2. If the first element is an even number and the last an odd number, the first and last elements are to be coded as '('.
  3. If both second and third elements are perfect squares, the code of the third element will be the code for the second element.

What will be the code for the following group?
4739

A
(JK(
B
(KJ(
C
HKJN
D
HJKN
Result Summary
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APEDIA

NTPC Graduate Tier 1
2025 • 05 Jun, 2025 • Shift-3
A group of numbers and symbols is coded using letter codes as per the codes given below and the conditions that follow.

Number/symbol4@7#3&82A9$6+
CodeHAJBKCLDMENFG


Conditions:
  1. If the first element is a number and the last a symbol, the codes for these two (the first and the last elements) are to be interchanged.
  2. If the first element is an even number and the last an odd number, the first and last elements are to be coded as '('.
  3. If both second and third elements are perfect squares, the code of the third element will be the code for the second element.

What will be the code for the following group?
4739
Correct Answer
(JK(
[Condition Scanning Matrix]: We analyze the input string '4739' strictly against the stated hierarchy of operational rules.[First Constraint Test]: The first el......
💡 Analysis & Explanation
[Condition Scanning Matrix]
We analyze the input string '4739' strictly against the stated hierarchy of operational rules.
[First Constraint Test]
The first element (4) is a number, but the last element (9) is also a number, not a symbol. Rule 1 does not apply.
[Second Constraint Test]
The first element is 4 (which is mathematically even). The last element is 9 (which is mathematically odd). This perfectly triggers Rule 2.
[Execution Phase]
Applying Rule 2, both the first and the last characters in the output string must be replaced by the literal symbol '('. The inner elements '7' and '3' are mapped directly to their standard codes 'J' and 'K' respectively.
Conclusion
Combining these transformations yields the sequence (JK(.