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NTPC Graduate Tier 1 2025 Shift-3 📅 05 Jun, 2025

This question is based on the words given below.

BAD FIG ICE NOT

In each of the words, each vowel is changed to the letter immediately following it in the English alphabetical order and each consonant is changed to the letter immediately preceding in the English alphabetical order. In how many letter clusters thus formed, will no vowel appear?

A
Two
B
None
C
Three
D
One
Result Summary
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NTPC Graduate Tier 1
2025 • 05 Jun, 2025 • Shift-3
This question is based on the words given below.

BAD FIG ICE NOT

In each of the words, each vowel is changed to the letter immediately following it in the English alphabetical order and each consonant is changed to the letter immediately preceding in the English alphabetical order. In how many letter clusters thus formed, will no vowel appear?
Correct Answer
Two
[Transformation Rules]: The operational mandate is precise: Vowels (A, E, I, O, U) undergo a +1 shift. Consonants undergo a -1 shift.[Cluster Evaluation]:1. BAD......
Ref/Book : NTPC Graduate Tier 1 2025
Ref. Subject Reasoning
Chapter -
Ref. Topic Coding-Decoding
Pg. No -
💡 Analysis & Explanation
Introduction ▼
[Transformation Rules]
The operational mandate is precise: Vowels (A, E, I, O, U) undergo a +1 shift. Consonants undergo a -1 shift. ▼
[Cluster Evaluation]
1. BAD ▼
B(consonant) -> A; A(vowel) -> B; D(consonant) -> C. The new cluster is ABC. This contains the vowel 'A'.
2. FIG ▼
F(consonant) -> E; I(vowel) -> J; G(consonant) -> F. The new cluster is EJF. This contains the vowel 'E'.
3. ICE ▼
I(vowel) -> J; C(consonant) -> B; E(vowel) -> F. The new cluster is JBF. This is entirely devoid of vowels.
4. NOT ▼
N(consonant) -> M; O(vowel) -> P; T(consonant) -> S. The new cluster is MPS. This is also entirely devoid of vowels.
[Final Tally] ▼
Only the outputs generated from ICE (JBF) and NOT (MPS) meet the criteria of having absolutely zero vowels present.
Conclusion ▼
There are exactly two such transformed clusters.
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