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RRB NTPC Graduate Tier 1 2025 Shift-1 📅 09 Jun, 2025

A, B, C, D, E and F live on six different floors of the same building. The lowermost floor in the building is numbered 1, the floor above it, number 2 and so on till the topmost floor is numbered 6.

The product of floors on which F and D live is 15. E lives immediately above C. The sum of floors on which A and D live is 7. What is the sum of floors on which A and E live?

A
6
B
5
C
8
D
7
Result Summary
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RRB NTPC Graduate Tier 1
2025 • 09 Jun, 2025 • Shift-1
A, B, C, D, E and F live on six different floors of the same building. The lowermost floor in the building is numbered 1, the floor above it, number 2 and so on till the topmost floor is numbered 6.

The product of floors on which F and D live is 15. E lives immediately above C. The sum of floors on which A and D live is 7. What is the sum of floors on which A and E live?
Correct Answer
6
Floor Product Deduction: The floors inhabited by F and D yield a product of 15. The only viable floor numbers between 1 and 6 that multiply to 15 are 3 and 5. T......
Ref/Book : RRB NTPC Graduate Tier 1 2025
Ref. Subject Reasoning
Chapter -
Ref. Topic Puzzle Test
Pg. No -
💡 Analysis & Explanation
Floor Product Deduction ▼
The floors inhabited by F and D yield a product of 15. The only viable floor numbers between 1 and 6 that multiply to 15 are 3 and 5. Thus, F and D occupy floors 3 and 5 in some order.
Sum Constraint Resolution ▼
The sum of A and D's floors is 7. If D is on floor 5, A must be on floor 2. If D is on floor 3, A must be on floor 4.
Adjacency Rule Application ▼
E lives immediately above C, meaning E and C occupy consecutive floors. Let's test the first scenario (D=5, A=2, F=3). This leaves floors 1, 4, and 6 vacant. No two consecutive floors are available for E and C, rendering this scenario impossible. Testing the second scenario (D=3, A=4, F=5) leaves floors 1, 2, and 6 vacant. Floors 1 and 2 are consecutive, satisfying the condition perfectly. Therefore, E lives on 2, and C lives on 1. B takes the remaining floor 6.
Final Target Computation ▼
We need the sum of floors of A and E. Floor of A is 4, and floor of E is 2. The sum is 4 + 2 = 6.
Conclusion ▼
The total sum equals 6.
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