A group of numbers/symbols is coded using letter codes as per the codes given below and the conditions that follow. If none of the conditions apply, then codes for the respective number/symbol to be followed directly as given in the table.

Table:
8=L, 9=C, @=Z, &=N, 5=D, 7=W, 2=A, %=P, 1=R, 3=T, A=F, 4=B, 6=K

Conditions:
(i) If the first element is a symbol and the last a number, the codes for these two are to be interchanged.
(ii) If the first element is an odd number and the last an even number, the first and last elements are to be coded as X.
(iii) If both the second and third elements are perfect squares, the third element is to be coded as the code for the second element.

What will be the code for the following group: 76@13&

WKZRTW

WKRZTN

NKZRTN

WKZRTN

APEDIA

RRB NTPC Graduate Tier 1

2025 • 09 Jun, 2025 • Shift-1

A group of numbers/symbols is coded using letter codes as per the codes given below and the conditions that follow. If none of the conditions apply, then codes for the respective number/symbol to be followed directly as given in the table.

Table:
8=L, 9=C, @=Z, &=N, 5=D, 7=W, 2=A, %=P, 1=R, 3=T, A=F, 4=B, 6=K

Conditions:
(i) If the first element is a symbol and the last a number, the codes for these two are to be interchanged.
(ii) If the first element is an odd number and the last an even number, the first and last elements are to be coded as X.
(iii) If both the second and third elements are perfect squares, the third element is to be coded as the code for the second element.

What will be the code for the following group: 76@13&

Correct Answer

WKZRTN

Condition Evaluation: We break down the target sequence: 76@13&. The first element is '7' (an odd number) and the final element is '&' (a symbol). Checking the ......

💡 Analysis & Explanation

Condition Evaluation ▼

We break down the target sequence: 76@13&. The first element is '7' (an odd number) and the final element is '&' (a symbol). Checking the provided constraints: Condition (i) fails because the first element is not a symbol. Condition (ii) fails because the last element is not an even number. Condition (iii) fails because the third element '@' is a symbol, not a perfect square.

Direct Substitution Execution ▼

Since absolutely no overriding special conditions apply to this specific string, we proceed to translate the sequence character by character using the direct mapping from the provided cipher table.

Mapping Translation ▼

Translating sequentially: 7 becomes W, 6 becomes K, @ becomes Z, 1 becomes R, 3 becomes T, and & becomes N.

Conclusion ▼

Seamlessly merging these translated alphabetical codes yields the final string WKZRTN.

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