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Arithmetic
Time and Work
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RRB NTPC Graduate Tier 1 2025 Shift-1 📅 09 Jun, 2025

A water tank can be filled in 29 minutes by using 23 pipes of the same capacity. In how many minutes (rounded off to two decimal places) will the water tank be filled if we use 47 pipes of the same capacity as above?

A
21.97
B
17.43
C
14.19
D
24.44
Result Summary
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RRB NTPC Graduate Tier 1
2025 • 09 Jun, 2025 • Shift-1
A water tank can be filled in 29 minutes by using 23 pipes of the same capacity. In how many minutes (rounded off to two decimal places) will the water tank be filled if we use 47 pipes of the same capacity as above?
Correct Answer
14.19
Work Equivalence Setup: In time and work problems involving constant rates, the total required effort (or volume) can be represented mathematically as the produ......
Ref/Book : RRB NTPC Graduate Tier 1 2025
Ref. Subject Arithmetic
Chapter -
Ref. Topic Time and Work
Pg. No -
💡 Analysis & Explanation
Work Equivalence Setup ▼
In time and work problems involving constant rates, the total required effort (or volume) can be represented mathematically as the product of the number of workers (or pipes) and the time taken. Thus, Total Work capacity = 23 pipes * 29 minutes.
Inverse Proportion Calculation ▼
Let 'T' mathematically represent the unknown time required when deploying 47 pipes. Since the total work remains constant, we set up the equation: 47 * T = 23 * 29.
Solving for Time ▼
First, multiply the right side of the equation: 23 * 29 = 667. Next, isolate T by dividing by the new higher number of pipes: T = 667 / 47. Performing this division yields approximately 14.19148 minutes.
Conclusion ▼
Rounding strictly to two decimal places as requested, the required operational time is 14.19 minutes.
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