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Arithmetic
Time, Speed and Distance
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RRB NTPC Graduate Tier 1 2025 Shift-1 📅 09 Jun, 2025

While covering a distance of 54 km, a man noticed that after cycling for 1 hour 15 minutes, the distance covered by him was 7/9 of the remaining distance. What was his speed (in km/hr)?

A
18.7
B
18.9
C
19.9
D
19.5
Result Summary
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RRB NTPC Graduate Tier 1
2025 • 09 Jun, 2025 • Shift-1
While covering a distance of 54 km, a man noticed that after cycling for 1 hour 15 minutes, the distance covered by him was 7/9 of the remaining distance. What was his speed (in km/hr)?
Correct Answer
18.9
Distance Segregation Analysis: Let the total distance be divided into two parts: the covered distance (D) and the remaining distance (R). The problem states the......
Ref/Book : RRB NTPC Graduate Tier 1 2025
Ref. Subject Arithmetic
Chapter -
Ref. Topic Time, Speed and Distance
Pg. No -
💡 Analysis & Explanation
Distance Segregation Analysis ▼
Let the total distance be divided into two parts: the covered distance (D) and the remaining distance (R). The problem states the total distance is 54 km, so D + R = 54.
Proportional Setup ▼
We are given that D = (7/9) * R. Substituting this into the total distance equation yields: (7/9)R + R = 54, which simplifies to (16/9)R = 54. Solving for R gives 54 * 9 / 16 = 30.375 km.
Distance Covered Calculation ▼
The distance covered D is 54 - 30.375 = 23.625 km.
Speed Computation ▼
The time taken to cover this distance is 1 hour 15 minutes, which equates to 1.25 hours. Speed = Distance / Time = 23.625 / 1.25 = 18.9 km/hr.
Conclusion ▼
His calculated constant speed was 18.9 km/hr.
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