Each of C, D, E, F, S, T and U has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. Only two people have the exam before T. Only one person has the exam after D. Only three people have the exam between T and F. Only one person has the exam between E and C. U has the exam immediately before E. Who among the following has the exam on Friday?

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NTPC Graduate Tier 1

2025 • 05 Jun, 2025 • Shift-2

Each of C, D, E, F, S, T and U has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. Only two people have the exam before T. Only one person has the exam after D. Only three people have the exam between T and F. Only one person has the exam between E and C. U has the exam immediately before E. Who among the following has the exam on Friday?

Correct Answer

Fixed Anchors: Map the week from Mon (1) to Sun (7). 'Two people before T' decisively locks T on Wednesday (Day 3). 'One person after D' locks D on Saturday (Da......

💡 Analysis & Explanation

Fixed Anchors ▼

Map the week from Mon (1) to Sun (7). 'Two people before T' decisively locks T on Wednesday (Day 3). 'One person after D' locks D on Saturday (Day 6).

Spacing Constraints ▼

'Three people between T and F' places F entirely on Sunday (Day 7), since Wed + 3 days interval leads to Sunday.

Clustered Placements ▼

'U is immediately before E' creates a block (UE). This block cannot fit Thu/Fri because placing E on Friday prevents 'one person between E and C' (Sunday is blocked by F, Wednesday by T). Thus, the UE block must occupy Monday and Tuesday.

Final Gap Filling ▼

Now, Monday=U, Tuesday=E, Wednesday=T. 'One person between E and C' forces C onto Thursday (Day 4). The only remaining slot is Friday, which must logically be given to the final person, S.

Conclusion ▼

S perfectly fits the Friday schedule.

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