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RRB NTPC Graduate Tier 1 2025 Shift-2 📅 06 Jun, 2025

Find the surface area of a sphere whose diameter is equal to 112 cm.

A
36,976 cm²
B
38,980 cm²
C
37,948 cm²
D
39,424 cm²
Result Summary
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RRB NTPC Graduate Tier 1
2025 • 06 Jun, 2025 • Shift-2
Find the surface area of a sphere whose diameter is equal to 112 cm.
Correct Answer
39,424 cm²
Determining Radius: The problem provides the diameter of the sphere as 112 cm. The radius (r) is exactly half of the diameter, so r = 112 / 2 = 56 cm.Applying t......
Ref/Book : RRB NTPC Graduate Tier 1 2025
Ref. Subject Mathematics
Chapter -
Ref. Topic Mensuration
Pg. No -
💡 Analysis & Explanation
Determining Radius ▼
The problem provides the diameter of the sphere as 112 cm. The radius (r) is exactly half of the diameter, so r = 112 / 2 = 56 cm.
Applying the Formula ▼
The total surface area of a perfect sphere is calculated using the formula A = 4πr².
Execution of Calculation ▼
Substitute the values into the equation: A = 4 × (22/7) × 56 × 56. Simplify the fraction by dividing 56 by 7, leaving 8. The equation becomes A = 4 × 22 × 8 × 56.
Final Arithmetic ▼
Multiply the parts: 88 × 448 = 39,424 cm².
Conclusion ▼
The accurate surface area is 39,424 cm².
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