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NTPC Graduate Tier 1 2025 Shift-2 📅 06 Jun, 2025

The volume of a solid cylinder is 5852 cm³ and its height is 38 cm. What is the total surface area of the solid cylinder? (Round your answer to the nearest integer) (Use π = 22/7)

A
1969 cm²
B
1980 cm²
C
1954 cm²
D
1936 cm²
Result Summary
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APEDIA

NTPC Graduate Tier 1
2025 • 06 Jun, 2025 • Shift-2
The volume of a solid cylinder is 5852 cm³ and its height is 38 cm. What is the total surface area of the solid cylinder? (Round your answer to the nearest integer) (Use π = 22/7)
Correct Answer
1980 cm²
Finding the Radius: The volume of a cylinder is governed by the formula V = πr²h. Substituting the known values gives 5852 = (22/7) × r² × 38. Rearranging ......
Ref/Book : NTPC Graduate Tier 1 2025
Ref. Subject Mathematics
Chapter -
Ref. Topic Mensuration
Pg. No -
💡 Analysis & Explanation
Finding the Radius ▼
The volume of a cylinder is governed by the formula V = πr²h. Substituting the known values gives 5852 = (22/7) × r² × 38. Rearranging to solve for r² yields r² = (5852 × 7) / (22 × 38) = 49. Therefore, the radius r is 7 cm.
Surface Area Formula Application ▼
The total surface area (TSA) of a solid right circular cylinder is calculated using the formula TSA = 2πr(r + h).
Final Value Calculation ▼
Substituting r = 7 cm and h = 38 cm into the TSA equation gives 2 × (22/7) × 7 × (7 + 38). This simplifies purely to 44 × 45 = 1980 cm².
Conclusion ▼
The total surface area evaluates exactly to 1980 cm².
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