SSC CGL

2025

Second Shift

English 25

All Questions 25 Active Passive Voice 2 Antonyms 1 Direct Indirect Speech 2 Error Spotting 2 Fill in the Blanks 3 Idioms 1 One Word Substitution 1 Para Jumbles 2 Reading Comprehension 5 Sentence Improvement 2 Spelling Correction 2 Synonyms 1 Vocabulary 1

General Awareness 25

All Questions 25 Art and Culture 1 Biology 1 Books and Authors 1 Current Affairs 4 Economics 2 Environment 1 Geography 3 Government Schemes 2 History 2 Physics 2 Polity 3 Science 1 Sports 2

Maths 25

All Questions 25 Algebra 2 Arithmetic 1 Average 1 Compound Interest 1 Coordinate Geometry 1 Geometry 3 Mensuration 2D 1 Mixtures 1 Number System 1 Partnership 2 Percentage 1 Profit and Loss 1 Ratio and Proportion 2 Simplification 1 Time and Work 2 Time Speed and Distance 1 Trigonometry 3

Reasoning 25

All Questions 25 Alphabet Test 1 Arithmetical Reasoning 2 Blood Relations 3 Classification 1 Coding-Decoding 2 Data Checking 1 Letter Analogy 1 Letter Series 2 Mathematical Operations 2 Number Classification 1 Number Series 3 Ranking 1 Statement and Assumption 1 Syllogism 1 Word Analogy 2 Word Formation 1

Maths

Mensuration 2D

EN हिंदी

✕

SSC CGL 2025 Second Shift 📅 12 Sep, 2025

A circular park having a radius of 14 m. If a 1.5 m wide path is built around it, what is the approximate area of the path?

A

139 m²

B

135 m²

C

142 m²

D

150 m²

Result Summary

APEDIA

SSC CGL

2025 • 12 Sep, 2025 • Second Shift

A circular park having a radius of 14 m. If a 1.5 m wide path is built around it, what is the approximate area of the path?

Correct Answer

139 m²

Area = π * (15.5² - 14²) = π * (240.25 - 196) = 44.25π ≈ 139 m².[span_65](start_span)[span_65](end_span)...

💡 Analysis & Explanation

Introduction ▼

Area = π * (15.5² - 14²) = π * (240.25 - 196) = 44.25π ≈ 139 m².[span_65](start_span)[span_65](end_span)