BPSC Prelims

2023

General

Bihar Special 16

All Questions 16 Culture 2 Demography 1 Environment 2 Geography 3 Geology 1 History 6 Minerals 1

Computer 1

All Questions 1 Languages 1

Current Affairs 18

All Questions 18 Culture 1 Defence 1 Disaster 1 Economy 2 Environment 3 International 5 National 1 Paleontology 1 Reports 1 Sports 1 Tourism 1

Economy 15

All Questions 15 Banking 1 Budget 1 Currency 1 Demography 1 Energy 1 External Sector 1 Fiscal Policy 1 Globalization 1 Human Capital 1 Industry 1 Inflation 1 Schemes 2 Survey 1 Trade 1

Education 1

All Questions 1 Policy 1

Environment 2

All Questions 2 Biosphere 1 Species 1

General Awareness 3

All Questions 3 International 1 Lifestyle 1 Sports 1

General Science 19

All Questions 19 Biology 5 Chemistry 5 Diseases 2 Physics 7

Geography 14

All Questions 14 Climatology 1 India 2 Minerals 1 Oceanography 1 Physical 5 Rivers 1 Universe 1 World 2

History 30

All Questions 30 Ancient 6 Culture 3 Medieval 6 Modern 13 World History 2

Mental Ability 10

All Questions 10 Classification 2 Coding 2 Direction 1 Distance 1 Missing Number 1 Problem Solving 1 Series 1 Syllogism 1

Polity 14

All Questions 14 Amendment 1 Constitution 3 Emergency 1 Fundamental Rights 1 Judiciary 3 Parliament 1 Parties 1 Rights 1 Schedules 1 States 1

Science & Tech 7

All Questions 7 AI 1 Biology 2 Materials 1 Robotics 1 Space 1 Telecommunication 1

Mental Ability

Distance

EN हिंदी

✕

BPSC Prelims 2023 General 📅 30 Sep, 2023

M is 4km North of N. P is 2km South of O. N is 1km SE of O. Dist between M and P?

A

5.34

B

6.74

C

28.5

D

None

Result Summary

APEDIA

BPSC Prelims

2023 • 30 Sep, 2023 • General

M is 4km North of N. P is 2km South of O. N is 1km SE of O. Dist between M and P?

Correct Answer

5.34

Coordinates (Assuming O at 0,0): - O (0,0). - P (0, -2). - N (1km SE of O). SE implies 45 deg. Coordinates $(\frac{1}{\sqrt{2}}, -\frac{1}{\sqrt{2}})$.......

💡 Analysis & Explanation

Coordinates (Assuming O at 0,0) ▼

- O (0,0).
- P (0, -2).
- N (1km SE of O). SE implies 45 deg. Coordinates $(\frac{1}{\sqrt{2}}, -\frac{1}{\sqrt{2}})$.
- M (4km North of N). Coordinates $(\frac{1}{\sqrt{2}}, 4 - \frac{1}{\sqrt{2}})$.

Distance MP ▼

$\sqrt{(x_M-x_P)^2 + (y_M-y_P)^2}$.
- $x_M = 0.707, x_P = 0$. Diff = 0.707.
- $y_M = 3.293, y_P = -2$. Diff = 5.293.
- Dist = $\sqrt{0.5 + 28} \approx \sqrt{28.5} \approx 5.34$.

Answer ▼

5.34 km.