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Arithmetic
Time and Work
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NTPC Graduate Tier 1 2016 Shift 2 📅 02 Apr, 2016

30 men working 5 hours a day can do a task in 16 days. In how many days will 40 men working 6 hours a day do the same task?

A
12 days
B
10 days
C
15 days
D
18 days
Result Summary
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NTPC Graduate Tier 1
2016 • 02 Apr, 2016 • Shift 2
30 men working 5 hours a day can do a task in 16 days. In how many days will 40 men working 6 hours a day do the same task?
Correct Answer
10 days
Work Equivalence Principle: The fundamental rule of Time and Work states that the total work done is directly proportional to the product of Men, Days, and Hour......
Ref/Book : NTPC Graduate Tier 1 2016
Ref. Subject Arithmetic
Chapter -
Ref. Topic Time and Work
Pg. No -
💡 Analysis & Explanation
Work Equivalence Principle ▼
The fundamental rule of Time and Work states that the total work done is directly proportional to the product of Men, Days, and Hours. Formula: M1 * D1 * H1 = M2 * D2 * H2.
Inputting Data Set 1 ▼
For the first scenario, Men (M1) = 30, Days (D1) = 16, Hours (H1) = 5. Total Work Unit = 30 * 16 * 5 = 2400 units.
Inputting Data Set 2 ▼
For the second scenario, Men (M2) = 40, Hours (H2) = 6. We need to find Days (D2). So, 40 * D2 * 6 = 2400.
Solving the Equation ▼
This simplifies to 240 * D2 = 2400. Dividing both sides by 240 yields D2 = 10.
Conclusion ▼
Under the new conditions, it will take precisely 10 days to complete the task.
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