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Arithmetic
Ratio & Proportion
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NTPC Graduate Tier 1 2016 Shift 2 📅 02 Apr, 2016

Divide 3740 in three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal.

A
700, 1000, 2040
B
340, 1360, 2040
C
680, 1020, 2040
D
500, 1200, 2040
Result Summary
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NTPC Graduate Tier 1
2016 • 02 Apr, 2016 • Shift 2
Divide 3740 in three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal.
Correct Answer
680, 1020, 2040
Algebraic Formulation: Let the three distinct parts be represented as x, y, and z. The condition states that x/2 = y/3 = z/6 = k (a constant ratio).Variable Exp......
Ref/Book : NTPC Graduate Tier 1 2016
Ref. Subject Arithmetic
Chapter -
Ref. Topic Ratio & Proportion
Pg. No -
💡 Analysis & Explanation
Algebraic Formulation ▼
Let the three distinct parts be represented as x, y, and z. The condition states that x/2 = y/3 = z/6 = k (a constant ratio).
Variable Expression ▼
From this, we can express each part in terms of k: x = 2k, y = 3k, and z = 6k.
Summation Equation ▼
The sum of all parts equals the total amount, so 2k + 3k + 6k = 3740, which simplifies to 11k = 3740.
Solving for Constant ▼
Dividing 3740 by 11 gives k = 340.
Final Values Calculation ▼
Multiplying k yields the parts: x = 2*340 = 680, y = 3*340 = 1020, and z = 6*340 = 2040.
Conclusion ▼
The three parts are correctly divided as 680, 1020, and 2040.
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