When x is added to each of 30, 15, 21 and 11, then the numbers so obtained, in this order, are in proportion. Then, if $6x : y :: y : (3x-9)$, and $y0$, what is the value of y?

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When x is added to each of 30, 15, 21 and 11, then the numbers so obtained, in this order, are in proportion. Then, if $6x : y :: y : (3x-9)$, and $y>0$, what is the value of y?

Apedia · Accepted Answer

Correct Answer: 18.

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When x is added to each of 30, 15, 21 and 11, then the numbers so obtained, in this order, are in proportion. Then, if $6x : y :: y : (3x-9)$, and $y>0$, what is the value of y?