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NTPC Graduate Tier 1 2025 Shift-2 📅 06 Jun, 2025

A, B, C, D, E and F live on six different floors of the same building. The lowermost floor in the building is numbered 1, the floor above it, number 2 and so on till the topmost floor is numbered 6. The product of floors on which D and F live is 10. C lives immediately above E. The sum of floors on which B and D live is 11. How many people live between A and E?

A
3
B
1
C
2
D
4
Result Summary
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APEDIA

NTPC Graduate Tier 1
2025 • 06 Jun, 2025 • Shift-2
A, B, C, D, E and F live on six different floors of the same building. The lowermost floor in the building is numbered 1, the floor above it, number 2 and so on till the topmost floor is numbered 6. The product of floors on which D and F live is 10. C lives immediately above E. The sum of floors on which B and D live is 11. How many people live between A and E?
Correct Answer
1
Mathematical Constraints Analysis: D and F live on floors whose product is 10. The only possible distinct floor numbers between 1 and 6 that multiply to 10 are ......
💡 Analysis & Explanation
Mathematical Constraints Analysis
D and F live on floors whose product is 10. The only possible distinct floor numbers between 1 and 6 that multiply to 10 are 2 and 5. Also, B + D = 11. The only possible floors are 5 and 6.
Positioning Key Members
Since D is common to both conditions, D must live on floor 5. Therefore, F lives on floor 2 (5×2=10) and B lives on floor 6 (6+5=11).
Placing the Remaining
Floors 1, 3, and 4 are empty. C lives immediately above E, meaning they need consecutive floors. This leaves floors 4 and 3 for C and E respectively. A must occupy the only remaining floor, which is floor 1.
Conclusion
The floor layout is: 6(B), 5(D), 4(C), 3(E), 2(F), 1(A). Between A(1) and E(3), only 1 person (F on floor 2) lives.