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NTPC Graduate Tier 1 2025 Shift-2 📅 06 Jun, 2025

Find the angle of elevation of the top of a 250√3 m high tower, from a point which is 250 m away from its foot.

A
75°
B
60°
C
45°
D
30°
Result Summary
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NTPC Graduate Tier 1
2025 • 06 Jun, 2025 • Shift-2
Find the angle of elevation of the top of a 250√3 m high tower, from a point which is 250 m away from its foot.
Correct Answer
60°
Trigonometric Setup: The specific scenario natively forms a right-angled triangle where the structural tower acts as the perpendicular height (250√3 m) and th......
Ref/Book : NTPC Graduate Tier 1 2025
Ref. Subject Mathematics
Chapter -
Ref. Topic Heights and Distances
Pg. No -
💡 Analysis & Explanation
Trigonometric Setup ▼
The specific scenario natively forms a right-angled triangle where the structural tower acts as the perpendicular height (250√3 m) and the horizontal distance from the foot serves as the base length (250 m).
Applying Tangent Ratio ▼
In right-angle trigonometry, the tangent function of the angle of elevation (θ) fundamentally expresses the geometric ratio of the perpendicular side to the base side: tan(θ) = Perpendicular / Base.
Calculation ▼
Systematically substituting the given metric values, we get tan(θ) = (250√3) / 250. This fraction simplifies directly and elegantly to tan(θ) = √3.
Finding the Angle ▼
Referencing standard trigonometric identity tables, the specific angle whose tangent evaluates to √3 is precisely 60°.
Conclusion ▼
The true angle of elevation is exactly 60°.
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