Apedia Logo Apedia
Join

Choose Language

Select your preferred reading language
🇬🇧
English
✔
🇮🇳
हिन्दी
✔
✕
Full View
Mathematics
Pipes and Cisterns
EN हिंदी
✕
NTPC Graduate Tier 1 2025 Shift-2 📅 05 Jun, 2025

Two pipes, A and B, can fill a tank of 3700 litres in 9 hours and 6 hours, respectively. If they are opened together, how many hours will they take to fill an empty tank of 6400 litres?

A
1152/185 hours
B
1149/185 hours
C
1159/185 hours
D
1153/185 hours
Result Summary
Logo

APEDIA

NTPC Graduate Tier 1
2025 • 05 Jun, 2025 • Shift-2
Two pipes, A and B, can fill a tank of 3700 litres in 9 hours and 6 hours, respectively. If they are opened together, how many hours will they take to fill an empty tank of 6400 litres?
Correct Answer
1152/185 hours
Independent Velocity Assessment: Pipe A pumps water at a continuous rate of 3700/9 liters per hour. Concurrently, Pipe B thrusts water at 3700/6 liters per hour......
Ref/Book : NTPC Graduate Tier 1 2025
Ref. Subject Mathematics
Chapter -
Ref. Topic Pipes and Cisterns
Pg. No -
💡 Analysis & Explanation
Independent Velocity Assessment ▼
Pipe A pumps water at a continuous rate of 3700/9 liters per hour. Concurrently, Pipe B thrusts water at 3700/6 liters per hour.
Synergistic Rate Calculation ▼
Combined output equates to (3700/9) + (3700/6). Factoring out 3700 gives 3700 * (1/9 + 1/6) = 3700 * (5/18) = 18500/18 = 9250/9 liters per hour.
Capacity Constraint Application ▼
We must fill a massive new threshold of exactly 6400 liters using this combined pipeline speed.
Time Vector Projection ▼
Total Time required = Total Volume / Combined Rate. Consequently, Time = 6400 / (9250/9) = (6400 * 9) / 9250 = 57600 / 9250.
Conclusion ▼
Simplifying the massive fraction scales down directly to 1152/185 hours.
← Prev
37 / 100
Next →