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NTPC Graduate Tier 1 2025 Shift-2 📅 05 Jun, 2025

Uday starts from Point A and drives 3 km towards south. He then takes a right turn, drives 2 km, turns left and drives 5 km. He then takes a right turn and drives 3 km. He takes a final right turn, drives 8 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point A again (all turns are 90° turns only unless specified)?

A
3 km; East
B
5 km; West
C
4 km; East
D
5 km; East
Result Summary
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APEDIA

NTPC Graduate Tier 1
2025 • 05 Jun, 2025 • Shift-2
Uday starts from Point A and drives 3 km towards south. He then takes a right turn, drives 2 km, turns left and drives 5 km. He then takes a right turn and drives 3 km. He takes a final right turn, drives 8 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point A again (all turns are 90° turns only unless specified)?
Correct Answer
5 km; East
Initial Movement Mapping: Starting at origin (0,0), a 3km drive South puts Uday at (0, -3).Intermediate Trajectory: A right turn from facing South means turning......
💡 Analysis & Explanation
Initial Movement Mapping
Starting at origin (0,0), a 3km drive South puts Uday at (0, -3).
Intermediate Trajectory
A right turn from facing South means turning West. Driving 2km places him at (-2, -3). A subsequent left turn puts him back facing South. Driving 5km lands him at (-2, -8).
Final Routing Phase
A right turn from South faces West again. He moves 3km to (-5, -8). The ultimate right turn directs him North. He travels 8km exactly, arriving at Point P (-5, 0).
Distance Vector Analysis
Point A is at (0,0) and Point P is at (-5, 0). He is currently positioned exactly 5km purely on the Western axis from his origin.
Conclusion
To directly return to Point A, he must drive 5 km straight East.