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NTPC Graduate Tier 1 2025 Shift-3 📅 05 Jun, 2025

From a taxi stand, two cabs start at a speed of 54 km/hr at an interval of 29 minutes, both cabs travelling in the same direction. A man coming in the opposite direction towards the taxi stand meets the cabs at an interval of 12 minutes. Find the speed (in km/hr) of the man.

A
74.8
B
82.1
C
76.5
D
80.4
Result Summary
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APEDIA

NTPC Graduate Tier 1
2025 • 05 Jun, 2025 • Shift-3
From a taxi stand, two cabs start at a speed of 54 km/hr at an interval of 29 minutes, both cabs travelling in the same direction. A man coming in the opposite direction towards the taxi stand meets the cabs at an interval of 12 minutes. Find the speed (in km/hr) of the man.
Correct Answer
76.5
[Distance Blueprint]: The initial physical distance established between the two cabs is generated by the first cab traveling alone for 29 minutes at 54 km/hr. D......
💡 Analysis & Explanation
[Distance Blueprint]
The initial physical distance established between the two cabs is generated by the first cab traveling alone for 29 minutes at 54 km/hr. Distance = 54 × (29 / 60) km.
[Relative Motion Logic]
When the man (traveling at 'v' km/hr) encounters the first cab, the second cab is exactly that distance away. Since they move in opposite directions, their relative approach speed is (54 + v) km/hr.
[Equation Formulation]
This distance is covered at the relative speed in exactly 12 minutes. So, (54 + v) × (12 / 60) = 54 × (29 / 60).
[Mathematical Resolution]
Cancelling the 60s from the denominators gives 12 × (54 + v) = 1566. Dividing by 12 yields 54 + v = 130.5. Consequently, v = 130.5 - 54 = 76.5 km/hr.
Conclusion
The pedestrian's speed is 76.5 km/hr.