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RRB NTPC Graduate Tier 1 2016 Shift 2 📅 02 Apr, 2016

If R019 is divisible by 11, find the value of the smallest natural number R?

A
5
B
6
C
7
D
8
Result Summary
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APEDIA

RRB NTPC Graduate Tier 1
2016 • 02 Apr, 2016 • Shift 2
If R019 is divisible by 11, find the value of the smallest natural number R?
Correct Answer
8
Divisibility Rule Application: A number is completely divisible by 11 if the strict difference between the sum of its digits in odd positions and the sum of its......
💡 Analysis & Explanation
Divisibility Rule Application
A number is completely divisible by 11 if the strict difference between the sum of its digits in odd positions and the sum of its digits in even positions is either 0 or a multiple of 11.
Summation of Positions
For the four-digit number R019, the sum of the digits in odd places (starting from the left) is R + 1. The sum of the digits in even places is 0 + 9 = 9.
Difference Calculation
The calculated difference is (R + 1) - 9 = R - 8. For this resultant value to equal 0 (which satisfies the divisibility condition), R must necessarily be 8.
Conclusion
The smallest natural single-digit number that completely fulfills this specific condition is 8.