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Reasoning
Number Sequence
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RRB NTPC Graduate Tier 1 2025 Shift-1 📅 09 Jun, 2025

If 1 is added to each odd digit and 2 is subtracted from each even digit in the number 5673128, what will be the difference between the digits which are third from the left and second from the right in the new number thus formed?

A
9
B
6
C
7
D
8
Result Summary
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RRB NTPC Graduate Tier 1
2025 • 09 Jun, 2025 • Shift-1
If 1 is added to each odd digit and 2 is subtracted from each even digit in the number 5673128, what will be the difference between the digits which are third from the left and second from the right in the new number thus formed?
Correct Answer
8
Digit Transformation Process: The original number is 5673128. We apply the rule: Add 1 to odd numbers (5+1=6, 7+1=8, 3+1=4, 1+1=2) and subtract 2 from even numb......
Ref/Book : RRB NTPC Graduate Tier 1 2025
Ref. Subject Reasoning
Chapter -
Ref. Topic Number Sequence
Pg. No -
💡 Analysis & Explanation
Digit Transformation Process ▼
The original number is 5673128. We apply the rule: Add 1 to odd numbers (5+1=6, 7+1=8, 3+1=4, 1+1=2) and subtract 2 from even numbers (6-2=4, 2-2=0, 8-2=6).
New Sequence Formation ▼
The newly generated number sequence from left to right becomes 6484206.
Positional Calculation ▼
The digit situated third from the left is 8. The digit situated second from the right is 0. Subtracting the two values: 8 - 0 = 8.
Conclusion ▼
The final calculated difference is 8.
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