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SSC CGL 2025 Second Shift 📅 12 Sep, 2025

If secA = 13/5 and A is acute, find sinA

A
5/13
B
12/13
C
13/12
D
13/5
Result Summary
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APEDIA

SSC CGL
2025 • 12 Sep, 2025 • Second Shift
If secA = 13/5 and A is acute, find sinA
Correct Answer
12/13
h=13, b=5, so p=12. sinA = p/h = 12/13.[span_74](start_span)[span_74](end_span)...
💡 Analysis & Explanation
Introduction
h=13, b=5, so p=12. sinA = p/h = 12/13.[span_74](start_span)[span_74](end_span)